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Im PDF ansehen(öffnet in einem neuen Fenster)[math.MG] 20 Jun 2008
The ancient Greeks present: Rational
Trigonometry
N J Wildberger
School of Mathematics and Statistics
UNSW Sydney 2052 Australia
webpages: http://web.maths.unsw.edu/~ norman/
June 20, 2008
Three ancient Greek theorems
There are three classical theorems about triangles that every mathematics student traditionally meets. To state these, consider a triangle A; 243 with side
lengths di = |A, As], do = |A1, Aal and d3 = |A1, Aal.
Pythagoras’ theorem The triangle A1 A2A3 has a right angle at Az precisely
when
d +d = di.
Area of triangle The area of a triangle is one half the length of the base times
the height.
Heron’s formula /f s = (di + d2 + da) /2 is the semi-perimeter of a triangle,
then its area is
area = y/s(s — di) (s — da) (s — da).
Deer
N,d
WILD BERGER
+63 +
arX 1V 0806.3481v1
Abstract
Pythagoras’ theorem, the area of a triangle as one half the base times
the height, and Heron’s formula are amongst the most important and
useful results of ancient Greek geometry. Here we look at all three in
a new and improved light, using quadrance not distance. This leads to
a simpler and more elegant trigonometry, in which angle is replaced by
spread, and which extends to arbitrary fields and more general quadratic
forms.
In this paper we will recast all three in simpler and more general forms. As
a reward, we find that rational trigonometry falls into our laps, essentially for
free. Our reformulation works over a general field (not of characteristic two),
in arbitrary dimensions, and even with an arbitrary quadratic form—sce [2], [3]
Seite 2
Im PDF ansehen(öffnet in einem neuen Fenster)arXiv:0806.3481v1 [math.MG] 20 Jun 2008
The ancient Greeks present: Rational
Trigonometry
N J Wildberger
School of Mathematics and Statistics
UNSW Sydney 2052 Australia
webpages: http://web.maths.unsw.edu/˜norman/
June 20, 2008
Abstract
Pythagoras’ theorem, the area of a triangle as one half the base times
the height, and Heron’s formula are amongst the most important and
useful results of ancient Greek geometry. Here we look at all three in
a new and improved light, using quadrance not distance. This leads to
a simpler and more elegant trigonometry, in which angle is replaced by
spread, and which extends to arbitrary fields and more general quadratic
forms.
Three ancient Greek theorems
There are three classical theorems about triangles that every mathematics student traditionally meets. To state these, consider a triangle A1 A2 A3 with side
lengths d1 ≡ |A2 , A3 |, d2 ≡ |A1 , A3 | and d3 ≡ |A1 , A2 |.
Pythagoras’ theorem The triangle A1 A2 A3 has a right angle at A3 precisely
when
d21 + d22 = d33 .
Area of triangle The area of a triangle is one half the length of the base times
the height.
Heron’s formula If s ≡ (d1 + d2 + d3 ) /2 is the semi-perimeter of a triangle,
then its area is
p
area = s (s − d1 ) (s − d2 ) (s − d3 ).
In this paper we will recast all three in simpler and more general forms. As
a reward, we find that rational trigonometry falls into our laps, essentially for
free. Our reformulation works over a general field (not of characteristic two),
in arbitrary dimensions, and even with an arbitrary quadratic form—see [2], [3]
Seite 3
Im PDF ansehen(öffnet in einem neuen Fenster)Pythagoras’ theorem
Euclid and other ancient Greeks regarded area, not distance, as the fundamental quantity in planar geometry. Indeed they worked with a straightedge and
compass in their constructions, not a ruler and protractor. A line segment
was measured by constructing a square on it, and determining the area of that
square. Two line segments were considered equal if they were congruent, but
this was independent of a direct notion of distance measurement.
Area is an affine concept : more precisely proportions between areas are
maintained by linear transformations. Even with a different metrical geometry,
for example a relativistic geometry in which x2 − y 2 plays the role of x2 + y 2 ,
the notion of signed area defined by a determinant applies. In other words,
in planar geometry area is a basic notion and may be considered prior to any
theory of linear measurement.
To Euclid, Pythagoras’ theorem is a relation about the areas of squares built
on each of the sides of a right triangle. This insight has largely been lost in the
modern formulation, but with a sheet of graph paper it is still an attractive way
to introduce students to the subject, as the area of many simple figures can be
computed by subdividing, translating and counting cells.
25
A2
5
A3
A1
20
Figure 1: Pythagoras’ theorem using areas
The squares on the sides of triangle A1 A2 A3 shown in Figure 1 have areas
5, 20 and 25. The largest square for example can be seen as four triangles which
can be rearranged to get two 3 × 4 rectangles, together with a 1 × 1 square,
for a total area of 25. So from this point of view Pythagoras’ theorem is a
result which can be established by counting, and the use of irrational numbers
to describe lengths is not necessary. This applies to any right triangle with
rational coordinates.
Seite 4
Im PDF ansehen(öffnet in einem neuen Fenster)Following the Greek terminology of ‘quadrature’, we define the quadrance
Q of a line segment to be the area of the square constructed on it. Pythagoras’
theorem allows us to assert that if A1 ≡ [x1 , y1 ] and A2 ≡ [x2 , y2 ] , then the
quadrance between A1 and A2 is
2
2
Q (A1 , A2 ) = (x2 − x1 ) + (y2 − y1 ) .
So for example the quadrance between the points [0, 0] and [1, 2] is Q = 5. The
usual distance between the points is the ‘square root’ of the quadrance and
requires
a prior theory of irrational numbers. Clearly the irrational number
√
5 ≈ 2. 236 067 977 . . . is a far more sophisticated and complicated object than
the natural number 5.
In statistics, variance is more natural than standard deviation. In quantum
mechanics, wave functions are more basic than probability amplitudes. In harmonic analysis, L2 is more pleasant than L1 . In geometry, quadrance is more
fundamental than distance.
For a triangle A1 A2 A3 we define the quadrances Q1 = Q (A2 , A3 ), Q2 =
Q (A1 , A3 ) and Q3 = Q (A1 , A2 ). Here then is Pythagoras’ theorem as the
Greeks viewed it —and it extends to arbitrary fields, to many dimensions, and
even with general quadratic forms.
Theorem 1 (Pythagoras) The lines A1 A3 and A2 A3 of the triangle A1 A2 A3
are perpendicular precisely when
Q1 + Q2 = Q3 .
Area of a triangle
The area of a triangle is one-half the base times the height. Let’s see how we
might remove some of the irrationalities that occur with this ancient formula
by looking at an example. The area of the triangle A1 A2 A3 in Figure 2 is one
A3
A2
A4
F
A1
Figure 2: A triangle and an associated parallelogram
half of the area of the associated parallelogram A1 A2 A3 A4 .
Seite 5
Im PDF ansehen(öffnet in einem neuen Fenster)The latter area may be calculated by removing from the circumscribed 12×8
rectangle four triangles, which can be combined to form two rectangles, one 5×3
and the other 7 × 5. The area of A1 A2 A3 is thus 23.
To apply the one-half base times height rule, the base A1 A2 by Pythagoras
has length
p
√
d3 = |A1 , A2 | = 72 + 52 = 74 ≈ 8. 602 325 267 04 . . ..
To find the length h of the altitude A3 F , set the origin to be at A1 , then the
line A1 A2 has Cartesian equation 5x − 7y = 0 while A3 = [2, 8] . A well-known
result from coordinate geometry then states that the distance h = |A3 , F | from
A3 to the line A1 A2 is
h=
46
|5 × 2 − 7 × 8|
√
= √ ≈ 5. 347 391 382 22 . . ..
52 + 72
74
If an engineer doing this calculation works with the
√ surd forms of both expressions, she will notice that the two occurrences of 74 conveniently cancel when
she takes one half the product of d3 and h, giving an area of 23. However if
she works immediately with the decimal forms, she may be surprised that her
calculator gives
area ≈
8. 602 325 267 04 . . . × 5. 347 391 382 22 . . .
≈ 23.000 000 000 01.
2
The usual formula forces us to descend to the level of irrational numbers and
square roots, even when the eventual answer is a natural number, and this
introduces unnecessary approximations and inaccuracies into the subject. It is
not hard to see how the use of quadrance allows us to reformulate the result.
Theorem 2 (Triangle area) The square of the area of a triangle is one-quarter
the quadrance of the base times the quadrance of the corresponding altitude.
As a formula, this would be
area2 =
Q×H
4
where Q is the quadrance of the base and H is the quadrance of the altitude to
that base.
Heron’s or Archimedes’ Theorem
The same triangle A1 A2 A3 of the previous section has side lengths
√
√
√
d1 = 34
d2 = 68
d3 = 74.
The semi-perimeter s, defined to be one half of the sum of the side lengths, is
then
√
√
√
34 + 68 + 74
s=
≈ 11. 339 744 206 6 . . ..
Seite 6
Im PDF ansehen(öffnet in einem neuen Fenster)Using the usual Heron’s formula, a computation with the calculator shows
that
√
√
√
area = s s − 34 s − 68 s − 74 ≈ 23.000 000.
Again we have a formula involving square roots in which there appears to be
a surprising integral outcome. Let’s now give another form of Heron’s formula,
with a new name. Arab sources suggest that Archimedes knew Heron’s formula
earlier, and the greatest mathematician of all time deserves credit for more than
he currently gets.
Theorem 3 (Archimedes) The area of a triangle A1 A2 A3 with quadrances
Q1 , Q2 and Q3 is given by
2
16 area2 = (Q1 + Q2 + Q3 ) − 2 Q21 + Q22 + Q23 .
In our example the triangle has quadrances 34, 68 and 74, each obtained by
Pythagoras’ theorem. So Archimedes’ theorem states that
2
16 area2 = (34 + 68 + 74) − 2 342 + 682 + 742 = 8464
and this gives an area of 23. In rational trigonometry, the quantity
2
A = (Q1 + Q2 + Q3 ) − 2 Q21 + Q22 + Q23
is the quadrea of the triangle, and turns out to be the single most important
number associated to a triangle. Note that
2
A = 4Q1 Q2 − (Q1 + Q2 − Q3 )
0
Q1
=−
Q2
1
Q1
0
Q3
1
Q2
Q3
0
1
1
1
.
1
0
It is instructive to see how to go from Heron’s formula to Archimedes’ theorem. In terms of the side lengths d1 , d2 and d3 :
16 area2 = (d1 + d2 + d3 ) (d1 + d2 − d3 ) (−d1 + d2 + d3 ) (d1 − d2 + d3 )
= (d1 + d2 )2 − d23 d23 − (d1 − d2 )2
2d1 d2 − d21 + d22 − d23
= 2d1 d2 + d21 + d22 − d23
2
= 4d21 d22 − d21 + d22 − d23
= 4Q1 Q2 − (Q1 + Q2 − Q3 )2
2
= (Q1 + Q2 + Q3 ) − 2 Q21 + Q22 + Q23 .
Archimedes’ theorem implies another formula of considerable importance.
Seite 7
Im PDF ansehen(öffnet in einem neuen Fenster)Theorem 4 (Triple quad formula) The three points A1 , A2 and A3 are collinear
precisely when
(Q1 + Q2 + Q3 )2 = 2 Q21 + Q22 + Q23 .
The proof is of course immediate, as collinearity is equivalent to the area of
the triangle being zero.
Spread between lines
An angle is the ratio of a circular distance to a linear distance, and this is
a complicated concept. To define an angle properly you require calculus, an
important point essentially understood by Archimedes. Vagueness about angles,
and the accompanying ambiguities in the definition of the circular functions
cos θ, sin θ and tan θ weaken most calculus texts.
There is a reason that classical trigonometry is painful to students—it is
based on the wrong notions. As a result, mathematics teachers are forced to
continually rely on 90 − 45 − 45 and 90 − 60 − 30 triangles for examples and test
questions, which makes the subject very narrow and repetitive.
Rational trigonometry, developed in [2], see also [4], shows how to simplify
and enrich the subject, leading to greater accuracy and quicker computations.
We want to show that the basic results of this new theory follow naturally from
the above presentation of Pythagoras’ theorem, the Triangle area theorem, and
Archimedes’ theorem.
The key innovation is to replace angle with a completely algebraic concept.
The separation between lines l1 and l2 is captured rather by the notion of spread,
which may be defined as the ratio of two quadrances as follows.
Suppose l1 and l2 intersect at the point A. Choose a point B 6= A on one of
the lines, say l1 , and let C be the foot of the perpendicular from B to l2 . Then
l1
B
Q
R
l2
A
C
s
Figure 3: Spread s between two lines l1 and l2
the spread s between l1 and l2 is
s = s (l1 , l2 ) =
Q (B, C)
Q
= .
Seite 8
Im PDF ansehen(öffnet in einem neuen Fenster)This ratio is independent of the choice of B, according to Thales, and is defined
between lines, not rays. Parallel lines are defined to have spread s = 0, while
perpendicular lines have spread s = 1.
The spread between the lines l1 and l2 with equations a1 x + b1 y + c1 = 0
and a2 x + b2 y + c2 = 0 turns out to be
2
s (l1 , l2 ) =
(a1 b2 − a2 b1 )
.
(a21 + b21 ) (a22 + b22 )
(1)
Since this is a rational expression, spread becomes a useful concept also over
general fields, although in this paper we stick to the usual situation over the
decimal numbers.
You may check that the spread corresponding to 30◦ or 150◦ or 210◦ or 330◦
is s = 1/4, the spread corresponding to 45◦ or 135◦ etc. is s = 1/2, and the
spread corresponding to 60◦ or 120◦ etc. is 3/4.
The following spread protractor was created by M. Ossmann [1].
Figure 4: A spread protractor
We use the notation that a triangle A1 A2 A3 has quadrances Q1 , Q2 and Q3 ,
as well as spreads s1 , s2 and s3 , labelled as in Figure 5. Note the diagrammatic
conventions that help us distinguish these quantities from distance and angle.
A3
s3
Q2
Q1
A1
s 2 A2
s1
Figure 5: Quadrances and spreads of a triangle
Seite 9
Im PDF ansehen(öffnet in einem neuen Fenster)Rational trigonometry
Let’s see how to combine the three ancient Greek theorems as restated above to
derive the main laws of rational trigonometry, independent of classical trigonometry, and without any need for transcendental functions. If H3 is the quadrance
of the altitude from A3 to the line A1 A2 , then the Triangle area theorem and
the definition of spread give
area2 =
Q 3 × H3
Q 3 Q 2 s1
Q 3 Q 1 s2
=
=
.
4
4
4
By symmetry, we get the following analog of the Sine law.
Theorem 5 (Spread law) For a triangle with quadrances Q1 , Q2 and Q3 , and
spreads s1 , s2 and s3 ,
s2
s3
4 area2
s1
=
=
=
.
Q1
Q2
Q3
Q1 Q2 Q3
By equating the formulas for 16 area2 obtained from the Triangle area theorem and Archimedes’ theorem, we get
2
4Q2 Q3 s1 = (Q1 + Q2 + Q3 ) − 2 Q21 + Q22 + Q23
= 2Q1 Q2 + 2Q1 Q3 + 2Q2 Q3 − Q21 − Q22 − Q23 .
Rearranging gives the following analog of the Cosine law.
Theorem 6 (Cross law) For a triangle with quadrances Q1 , Q2 and Q3 , and
spreads s1 , s2 and s3 ,
2
(Q1 − Q2 − Q3 ) = 4Q2 Q3 (1 − s1 ) .
Now substitute Q1 = s1 D, Q2 = s2 D and Q3 = s3 D, where D = Q1 Q2 Q3 /4 area2
from the Spread law into the Cross law, and cancel the common factor of D2 .
The result is the relation
2
(s1 − s2 − s3 ) = 4s2 s3 (1 − s1 )
between the three spreads of a triangle, which can be rewritten more symmetrically as follows.
Theorem 7 (Triple spread formula)
2
(s1 + s2 + s3 ) = 2 s21 + s22 + s23 + 4s1 s2 s3 .
This formula is a deformation of the Triple quad formula by a single cubic
term, and is the analog in rational trigonometry to the classical fact that the
three angles of a triangle sum to 3. 141 592 653 59 . . ..
The Triple quad formula, Pythagoras’ theorem, the Spread law, the Cross law
and the Triple spread formula are the five main laws of rational trigonometry.
Seite 10
Im PDF ansehen(öffnet in einem neuen Fenster)We now see these are closely linked to the geometrical work of the ancient
Greeks.
As demonstrated at some length in [2], these formulas and a few additional
ones suffice to solve the majority of trigonometric problems, usually more simply,
more accurately and more elegantly than the classical theory involving transcendental circular functions and their inverses. As shown in [3] and [5], the same
formulas extend to geometry over arbitrary fields (not of characteristic two) and
with general quadratic forms.
In retrospect, the blind spot first occurred with the Pythagoreans, who initially believed that all of nature should be expressible in terms of natural numbers and their proportions. When they discovered that the ratio of the length of
a diagonal
to the length of a side of a square was the incommensurable propor√
tion 2 : 1, legend has it that they tossed the exposer of the secret overboard
while at sea.
Had they maintained their beliefs in the workings of the Divine Mind, and
stuck with the squares of the lengths as the crucial quantities in geometry, then
mathematics would have had a significantly different history, Einstein’s special
theory of relativity would possibly have been discovered earlier, algebraic geometry would have quite another aspect, and students would today be studying a
simpler and more elegant trigonometry—much more happily!
References
[1] M.
Ossmann,
‘Print
a
Protractor’,
http://www.ossmann.com/protractor/.
download
online
at
[2] N. J. Wildberger, Divine Proportions: Rational Trigonometry to Universal
Geometry, Wild Egg Books, Sydney, 2005, http://wildegg.com.
[3] N. J. Wildberger, Affine and Projective Rational Trigonometry, 2006
arXiv:math/0612499.
[4] N. J. Wildberger, A Rational Approach to Trigonometry, Math Horizons,
Nov. 2007.
[5] N. J. Wildberger, One dimensional metrical geometry, Geometriae Dedicata,
128, no. 1, 145-166, 2007.