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Ver en el PDF(se abre en una ventana nueva)Ciak PA
Em ann A
IF PYTHAGORAS HAD A GEOBOARD ….
By WILLIAM A. EWBANK
Toylor University
Upland, Indiana
use a model at least 10 x 10 (i.c., 100
nails). Or one could use four smaller
boards together, provided the borders are
one-half the standard nail spacing (fig. 1).
THE theorem of Pythagoras is an old
.
.
.
.
.
.
favorite of junior and senior high mathematics teachers, and it lends itself to
much interesting discovery. This article
dezeribes an investigation into the famous
theorem, using geoboards.
“\
mathematician who developed the Cuizenrire-Gattegno system of colored rods. The
geoboard (or nailboard) is a flat board
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.
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.
.
.
.
into which nails or panel-pins have been
driven in à regular pattern. Geometric
.
.
fgures can then be formed, using rubber
hd
,
.
e
bands.
There are three types of geoboards in
use: (11 the square grid geoboard, (2) the
eıreular geoboard, and (3) the isometric
eri geoboard. This investigation used (1)
wid 13), which are analogs of squared
paper and isometric paper, respectively.
However, unlike paper, the geoboard is
tin a manner of speaking) a dynamic
device, and this I have found to be a
.
.
.
»
.
First, a word about the geoboard. The
invention of the geoboard has been credited to Dr. Caleb Gattegno, the British
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e
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à
°
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°
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4
Fig. 1
On this type of geohoard the arca of
any simple closed curve can easily be
found (that of a nonsimple closed curve
is a much harder task). It is best done
on the subtractive prineiple: by surroundobtainable from several educational suppliers (see listing at the end of this
article) or can easily be homemade. Howing the figure with a rect rete (nr a
polygonal figure with cach angle one or
three right angles), as shown in fig. 1. The
area of quadrilateral (a) is given by subtracting from the area of the square surrounding it (4 x 4, or 16), the sum of the
areas of triangles (b), (cj), (dj, and (e).
These are 15(3 x 2), M(2 x 1), MIZ x
1), and 12(3 x 1), respectively, or a total
of 7 units. Thus the quadrilateral (a)
has area 16 — 7, or 9 units. A facility with
calculations like this is essential for a
satisfactory investigation into the theorem
of Pythagoras.
Using this method, the student can set
‘ver. for this investigation, it is best to
up arrangements Jike those on the other
strong point in its favor in the classroom.
I do not know of any other teaching
li|
«vite at once so simple and so versatile.
At one end of the scale, it is attractive
to kindergarten children (Liedtke and
Kieren 1970), and at the other, it can
challenge the senior mathematics major in
“lege (Buckeye, Ewbank, and Ginther
1971),
sy far the best-known geoboard is the
“are grid model. It is inexpensive and
Matbemalics
lacher
March 1978
Página 2
Ver en el PDF(se abre en una ventana nueva)IF PYTHAGORAS HAD A GEOBOARD...
Author(s): WILLIAM A. EWBANK
Source: The Mathematics Teacher, Vol. 66, No. 3 (MARCH 1973), pp. 215-221
Published by: National Council of Teachers of Mathematics
Stable URL: http://www.jstor.org/stable/27959243 .
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Página 3
Ver en el PDF(se abre en una ventana nueva)IF PYTHAGORAS HAD A GEOBOARD .
By WILLIAM A. EWBANK
Taylor University
.
use a model at least 10 x
10 (i.e., 100
nails).
four
Or
one
could
use
smaller
boards together, provided the borders are
Upland, Indiana
one-half the standard nail spacing (fig. 1).
THE theorem of Pythagoras is an old
favorite of junior and senior high mathematics teachers,
and
it lends itself to
much interesting discovery. This article
describes an investigation into the famous
theorem, using geoboards.
First, a word about the geoboard. The
invention of the geoboard has been credited to Dr. Caleb Gattegno, the British
mathematician who developed the Cuisenaire-Gattegno system of colored rods. The
geoboard (or nailboard)
is a flat board
into which nails or panel-pins have been
driven in a regular pattern. Geometric
figures can then be formed, using rubber
bands.
There are three types of geoboards in
use: (1) the square grid geoboard, (2) the
Fig. 1
circular geoboard, and (3) the isometric
grid geoboard. This investigation used (1)
and
(8), which are analogs of squared
paper and isometric paper, respectively.
On this type of geoboard the area of
any simple closed
curve can
easily be
found (that of a nonsimple closed curve
However, unlike paper, the geoboard is
is a much harder task). It is best done
(in a manner of speaking)
on the subtractive principle: by surrounda dynamic
device, and this I have found to be a
ing the
strong point in its favor in the classroom.
polygonal figure with each angle one or
I do not know of any other teaching
three right angles), as shown in fig. 1. The
figure with
a
rectangle
(or a
device at once so simple and so versatile.
area of quadrilateral (a) is given by sub-
At one end of the scale, it is attractive
tracting from the area of the square surto
rounding it (4 X 4, or 16), the sum of the
kindergarten
children
(Liedtke
and
Kieren 1970), and at the other, it can
areas of triangles (b), (c), (d), and (e).
challenge the senior mathematics major in
These are 12(3 x 2), %(2 x 1),12(3 x
college
(Buckeye, Ewbank, and Ginther
1971).
1), and 44(3 x 1), respectively, or a total
of 7 units. Thus the quadrilateral
(a)
By far the best-known geoboard is the
has aréa 16 — 7, or 9 units. A facility with
square grid model. It is inexpensive and
calculations like this is essential for a
obtainable from several educational supsatisfactory investigation into the theorem
pliers
of Pythagoras.
(see
listing
at
the
end
of this
article) or can easily be homemade. How-
Using this method, the student can set
ever, for this investigation, it is best to
up arrangements like those on the other
March 1973
Página 4
Ver en el PDF(se abre en una ventana nueva)three boards
(fig. 1) to illustrate, with
the right triangles shown: top right, 1? +
1? = 2; lower left, 12 + 22 = 5; and
lower right, 2 + 2 = 2?.
An arrangement with a “skewed” right
triangle on a 10 X 10 geoboard is shown
in figure 2. The areas of the squares can
be calculated to be 2, 8, and 10.
Fig. 3
avoid the labor of marking out the lines,
it is recommended that a piece of isometric
graph paper be taped to the board. With
this, the nails can be driven through the
intersections at desired spacing (%” is
convenient), and the paper then removed.
With the board in hand, a snag arises
Fig. 2
which, at first sight, seems rather formidable: You cannot make a square on
If doubt arises as to whether a certain
triangle is, in fact, a right triangle, and if
the isometric geoboard! This makes it
impossible to check on the area of the
the students have had enough experiences
square on the side of any triangle, and
establishing the principles as illustrated
difficult to work out any area in square
above, they can use the converse of the
units.
theorem of Pythagoras to determine what
Now the basic unit of shape on the
sort of triangle they have made. Thus,
isometric board is the equilateral triangle.
if the area of the square on the longest
So why not use the area of the smallest
side of a triangle is equal to the sum of
equilateral triangle as our unit of area?
the areas of the squares on the two shorter
Figure 4 shows, with triangles of area 1,
sides, the triangle must be a right triangle.
4, and 9 and a hexagon of area 24, that
Figure 3 illustrates how a situation of
this system works well with simple figures.
inequality
In figure 5, the isosceles obtuse triangle
can
be
determined,
showing
that because 1 + 2 < 5, the first triangle
has area 1, because it is half of a rhombus
is obtuse, and because 2 + 5 > 5, the
of area 2. In figure 6 the obtuse triangle
second triangle is acute.
has area 2 because it is half of a paral-
The investigation now moves to the
lelogram of area 4. In this way the area
isometric geoboard. The isometric board
of any simple closed curve on the isois not nearly so well known. At the time
metric geoboard can be found. For exof writing I know of only one supplier in
ample, the area of quadrilateral
the United States (Math Media), but it
figure
7
can
be
found
by
(a)
in
subtracting
is fairly easy to make a board for yourfrom the area of the outside equilateral
self. As it is important that the nails be
triangle (side 6, area 36), the sum of the
as accurately lined up as possible and to
areas of triangles (b), (c), (d), (e), and
Mathematics Teacher
Página 5
Ver en el PDF(se abre en una ventana nueva)March 1973
Página 6
Ver en el PDF(se abre en una ventana nueva)(f). This gives 36 — (3+5+3+44+1),
a geoboard. So we must resort to paper
and pencil. From the numerical relationor 20.
To check this result, the quadrilateral can
ship
be decomposed into the triangles (p), (q),
(r), and (s), which have area 9 + 4 +
4 + 3, or 20.
Although squares cannot be made on
the isometric geoboard, rectangles can be
made, also right triangles (fig. 8). The
three rectangles in this diagram are congruent, and each is of area 15. The
diagonals divide them into congruent right
triangles.
Whenever right angles are formed, one
arm must lie on one of the three main
lines of nails, i.e., one of the axes of symmetry of the system. The reader is invited to attempt to form right angles in
other positions, and to satisfy himself that
it is not possible.
We are now ready to investigate Pythagoras further. Since it is possible to
make right triangles, but impossible to
make squares, why not try equilateral
triangles on the sides of a right triangle?
Figure 9 shows such an arrangement, and
calculation gives the areas of the equilateral triangles to be 3, 9, and 12. So far
Pythagoras, duly adapted, still holds
we can derive:
ka” = kb” + ke’,
where k is a constant.
We shall now establish a formula for
the area of a regular n-gon of side a.
Using the regular pentagon as model (fig.
12), we find:
180
a?
180
aa
area AABC
= 2 9 cot 5 “4 cot 5
a?
180
area pentagon = 5| — cot ——
4
5
na?
. area regular n-gon of side a = a
180
© t ra
= Ka?
where K is constant for the type of polygon under consideration. Since
Ka? = Kb’ + Kc
the theorem of Pythagoras must be true
for any given regular n-gon, and not just
for squares.
good!
What about figure 10? Does it work
here?
Since equilateral triangles will tessellate
to form regular hexagons, perhaps Pythagoras can be adapted as follows:
The area of the regular hexagon on
the hypotenuse of a right triangle 1s
equal to the area of the regular hexa-
/
ou!
ra ==
—
|A eee ;
+
(Py
À
Lis
a4
gons on the other two sides.
Figure 11 shows that this does appear
to be true, though of course one illustration does not prove the rule.
Let us assume that Pythagoras holds
good for equilateral triangles, squares, and
regular hexagons. Does it hold good for
any regular n-gon?
Due to the nature of the geoboard, this
cannot be checked, as only the above
three regular polygons can be formed on
218
Mathematics Teacher
j
j
B
O
a
Q
2
Fig. 12
What about nonpolygonal figures, e.g.,
semicircles? Is the following statement
true?
Página 7
Ver en el PDF(se abre en una ventana nueva)The area of the semicircle on the
An example of similar rectangles simhypotenuse of a right triangle 1s equal
to the sum of the areas of the semicircles on the other two sides.
ilarly placed is given in figure 14, and of
Just as above we found Pythagoras was
true for any given regular n-gon, since the
areas of regular n-gons are proportional to
the squares of their sides, so here, all we
scalene triangles in figure 15.
a
e
e
a
d
a
>
.
e
re
ra
4
>
have to do is to show that the areas of
semicircles are proportional to the squares
of their diameters. This is clearly so, since
the area of a semicircle of diameter a
2
would be rà Thus we have
stg
8
So far the adaptations of the Pythagorean theorem have been true only
for figures that are similar. Erect nonsimilar rectangles on the sides of a right
triangle, and obviously there will be no
area relationship, except by chance. Even
if the rectangles chosen were similar, e.g.,
with ratio of sides 2:1, their areas may
not satisfy the Pythagorean relationship.
This can easily be shown on a geoboard
It is not easy to make a series of similar
(fig. 13). This situation arises when the
Pythagorean theorem is adapted to figures
which, although similar, are not “similarly
nonregular polygons on a geoboard of
placed” or “positioned” on the triangle.
However, Euclid stated in Proposition 31
of Book VI of The Elements that “in
right-angled triangles, the rectilinear figure described on the side opposite the
right angle is equal to the similar and
similarly described figures upon the sides
containing the right angle.”
on the sides of a right triangle on an
limited size. In figure 16 an attempt has
been made to construct similar trapezoids
isometric board, but since
16 + 9% 24,
one of the trapezoids must be dissimilar.
It is fairly easy to see which one it is.
In figure 17 parallelograms have been
similarly placed on the sides of a right
triangle, again on an isometric board. This
time we can see that
36 + 10 # 44
and attempts to alter the largest parallelogram in shape only result in areas of
48 (fig. 18) or 52 (fig. 19).
It is probably easier to pursue investigations such as these on isometric dot
paper, and those with expansive ideas can
Fig. 13
stick two or more sheets together. Isometric dot paper is quite easily made by
March 1973
Página 8
Ver en el PDF(se abre en una ventana nueva)Mathematics Teacher
Página 9
Ver en el PDF(se abre en una ventana nueva)placing a piece of isometric graph paper
on top of a ditto mat and pricking through
vertices at regular intervals. Square grid
dot paper can be made, with tolerable
accuracy, with a typewriter and a ditto
mat.
The writer feels that with these simple
materials an interesting field of discovery
is open and that great value is to be found
in evolving simple rules to cope with
strange and novel situations.
REFERENCES
Buckeye, D. A, W. A. Ewbank, and J. L.
Ginther. A Cloudburst of Math Lab Ezxperiments. Vols. 3 and 4. Troy, Mich.: Midwest
Mathematics
textbooks that
stimulate learning
Publications, 1971.
Liedtke, Warner, and Thomas E. Kieren. “Geoboard Geometry for Preschool Children.”
ARITHMETIC TEACHER 17 (February 1970):
123-27.
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